What are the solutions to the equation 4d^2+4d+1=0 ?

The solutions to the equation 4d^2+4d+1=0 are d=-1/2

Find the zeros of 4d^2+4d+1=0

The zeros of 4d^2+4d+1=0 are d=-1/2

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4 d^{2} + 4 d + 1 = 0

d = - \frac{1}{2}

Decimal Notation

d = - 0.5

Solution steps

4 d^{2} + 4 d + 1 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

d_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

d = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

d = - \frac{1}{2}

The solution to the quadratic equation is:

d = - \frac{1}{2}

2 x^{2} - 25 = x^{2} + 9

x^{2} - 14 + 40 = 0

t, 0 = v t + \frac{1}{2} a t^{2}

c^{2} - 8 c = 0

r^{2} + 5 r = 0

What are the solutions to the equation 4d^2+4d+1=0 ?
The solutions to the equation 4d^2+4d+1=0 are d=-1/2
Find the zeros of 4d^2+4d+1=0
The zeros of 4d^2+4d+1=0 are d=-1/2