What are the solutions to the equation r^2+5r=0 ?

The solutions to the equation r^2+5r=0 are r=0,r=-5

Find the zeros of r^2+5r=0

The zeros of r^2+5r=0 are r=0,r=-5

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r^{2} + 5 r = 0

r = 0, r = - 5

Solution steps

r^{2} + 5 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

r_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 5 + 5}{2 \cdot 1}, r_{2} = \frac{- 5 - 5}{2 \cdot 1}

r = \frac{- 5 + 5}{2 \cdot 1} : 0

r = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

r = 0, r = - 5

s^{2} + 4 s - 60 = 0

4 x^{2} - 31 x - 45 = 0

x^{2} + 11 x = - 35

y = 0.00249 (1 - \frac{1.197 - 1100 y}{- 2})^{2}

(h - 4) (h - 10) = 0

What are the solutions to the equation r^2+5r=0 ?
The solutions to the equation r^2+5r=0 are r=0,r=-5
Find the zeros of r^2+5r=0
The zeros of r^2+5r=0 are r=0,r=-5