What are the solutions to the equation 4x^2-31x-45=0 ?

The solutions to the equation 4x^2-31x-45=0 are x=9,x=-5/4

Find the zeros of 4x^2-31x-45=0

The zeros of 4x^2-31x-45=0 are x=9,x=-5/4

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4 x^{2} - 31 x - 45 = 0

x = 9, x = - \frac{5}{4}

Decimal Notation

x = 9, x = - 1.25

Solution steps

4 x^{2} - 31 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 4 ( - 45 )}{2 \cdot 4}

(- 31)^{2} - 4 \cdot 4 (- 45) = 41

x_{1, 2} = \frac{- ( - 31 ) \pm 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 31 ) + 41}{2 \cdot 4}, x_{2} = \frac{- ( - 31 ) - 41}{2 \cdot 4}

x = \frac{- ( - 31 ) + 41}{2 \cdot 4} : 9

x = \frac{- ( - 31 ) - 41}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = 9, x = - \frac{5}{4}

x^{2} + 11 x = - 35

y = 0.00249 (1 - \frac{1.197 - 1100 y}{- 2})^{2}

(h - 4) (h - 10) = 0

m^{2} + 7 m - 8 = 0

0 = - 16 t^{2} + 85 t + 30

What are the solutions to the equation 4x^2-31x-45=0 ?
The solutions to the equation 4x^2-31x-45=0 are x=9,x=-5/4
Find the zeros of 4x^2-31x-45=0
The zeros of 4x^2-31x-45=0 are x=9,x=-5/4