What are the solutions to the equation 2x^2=4-7x ?

The solutions to the equation 2x^2=4-7x are x= 1/2 ,x=-4

Find the zeros of 2x^2=4-7x

The zeros of 2x^2=4-7x are x= 1/2 ,x=-4

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2 x^{2} = 4 - 7 x

x = \frac{1}{2}, x = - 4

Decimal Notation

x = 0.5, x = - 4

Solution steps

2 x^{2} = 4 - 7 x

Move

7 x

to the left side

2 x^{2} + 7 x = 4

Move

4

to the left side

2 x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 2}, x_{2} = \frac{- 7 - 9}{2 \cdot 2}

x = \frac{- 7 + 9}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 7 - 9}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 4

2 x^{2} - 15 x - 9 = 0

k = h + x^{2}

6 x^{2} - 2 = - 39

25 x^{2} = 12 (5 x - 3)

N (t) = 550 + 20 t - 0.2 t^{2}

What are the solutions to the equation 2x^2=4-7x ?
The solutions to the equation 2x^2=4-7x are x= 1/2 ,x=-4
Find the zeros of 2x^2=4-7x
The zeros of 2x^2=4-7x are x= 1/2 ,x=-4