What are the solutions to the equation 2x^2-15x-9=0 ?

The solutions to the equation 2x^2-15x-9=0 are x=(15+3sqrt(33))/4 ,x=(15-3sqrt(33))/4

Find the zeros of 2x^2-15x-9=0

The zeros of 2x^2-15x-9=0 are x=(15+3sqrt(33))/4 ,x=(15-3sqrt(33))/4

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2 x^{2} - 15 x - 9 = 0

x = \frac{15 + 3 33}{4}, x = \frac{15 - 3 33}{4}

Decimal Notation

x = 8.05842 \dots, x = - 0.55842 \dots

Solution steps

2 x^{2} - 15 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 15)^{2} - 4 \cdot 2 (- 9) = 333

x_{1, 2} = \frac{- ( - 15 ) \pm 3 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3 33}{2 \cdot 2}, x_{2} = \frac{- ( - 15 ) - 3 33}{2 \cdot 2}

x = \frac{- ( - 15 ) + 3 33}{2 \cdot 2} : \frac{15 + 3 33}{4}

x = \frac{- ( - 15 ) - 3 33}{2 \cdot 2} : \frac{15 - 3 33}{4}

The solutions to the quadratic equation are:

x = \frac{15 + 3 33}{4}, x = \frac{15 - 3 33}{4}

k = h + x^{2}

6 x^{2} - 2 = - 39

25 x^{2} = 12 (5 x - 3)

N (t) = 550 + 20 t - 0.2 t^{2}

n^{2} - 16 n = - 12

What are the solutions to the equation 2x^2-15x-9=0 ?
The solutions to the equation 2x^2-15x-9=0 are x=(15+3sqrt(33))/4 ,x=(15-3sqrt(33))/4
Find the zeros of 2x^2-15x-9=0
The zeros of 2x^2-15x-9=0 are x=(15+3sqrt(33))/4 ,x=(15-3sqrt(33))/4