What are the solutions to the equation 7^2=b^2+2^2 ?

The solutions to the equation 7^2=b^2+2^2 are b=3sqrt(5),b=-3sqrt(5)

Find the zeros of 7^2=b^2+2^2

The zeros of 7^2=b^2+2^2 are b=3sqrt(5),b=-3sqrt(5)

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7^{2} = b^{2} + 2^{2}

b = 35, b = - 35

Decimal Notation

b = 6.70820 \dots, b = - 6.70820 \dots

Solution steps

7^{2} = b^{2} + 2^{2}

Switch sides

b^{2} + 2^{2} = 7^{2}

Move

2^{2}

to the right side

b^{2} = 45

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 45, b = - 45

45 = 35

- 45 = - 35

b = 35, b = - 35

x^{2} - 49 = 0

6 x^{2} + 18 x = 24

a^{2} + 3 a = - 2

5 t^{2} - 14 t - 3 = 0

0.801 y^{2} + y - 1 = 0

What are the solutions to the equation 7^2=b^2+2^2 ?
The solutions to the equation 7^2=b^2+2^2 are b=3sqrt(5),b=-3sqrt(5)
Find the zeros of 7^2=b^2+2^2
The zeros of 7^2=b^2+2^2 are b=3sqrt(5),b=-3sqrt(5)