What are the solutions to the equation a^2+3a=-2 ?

The solutions to the equation a^2+3a=-2 are a=-1,a=-2

Find the zeros of a^2+3a=-2

The zeros of a^2+3a=-2 are a=-1,a=-2

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a^{2} + 3 a = - 2

a = - 1, a = - 2

Solution steps

a^{2} + 3 a = - 2

Move

2

to the left side

a^{2} + 3 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

a_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 3 + 1}{2 \cdot 1}, a_{2} = \frac{- 3 - 1}{2 \cdot 1}

a = \frac{- 3 + 1}{2 \cdot 1} : - 1

a = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = - 1, a = - 2

5 t^{2} - 14 t - 3 = 0

0.801 y^{2} + y - 1 = 0

64 = x^{2}

3 t^{2} - 10 t + 6 = 0

11 a^{2} + 12 a = 15

What are the solutions to the equation a^2+3a=-2 ?
The solutions to the equation a^2+3a=-2 are a=-1,a=-2
Find the zeros of a^2+3a=-2
The zeros of a^2+3a=-2 are a=-1,a=-2