What are the solutions to the equation 3t^2-10t+6=0 ?

The solutions to the equation 3t^2-10t+6=0 are t=(5+sqrt(7))/3 ,t=(5-sqrt(7))/3

Find the zeros of 3t^2-10t+6=0

The zeros of 3t^2-10t+6=0 are t=(5+sqrt(7))/3 ,t=(5-sqrt(7))/3

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3 t^{2} - 10 t + 6 = 0

t = \frac{5 + 7}{3}, t = \frac{5 - 7}{3}

Decimal Notation

t = 2.54858 \dots, t = 0.78474 \dots

Solution steps

3 t^{2} - 10 t + 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 6 = 27

t_{1, 2} = \frac{- ( - 10 ) \pm 2 7}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 10 ) + 2 7}{2 \cdot 3}, t_{2} = \frac{- ( - 10 ) - 2 7}{2 \cdot 3}

t = \frac{- ( - 10 ) + 2 7}{2 \cdot 3} : \frac{5 + 7}{3}

t = \frac{- ( - 10 ) - 2 7}{2 \cdot 3} : \frac{5 - 7}{3}

The solutions to the quadratic equation are:

t = \frac{5 + 7}{3}, t = \frac{5 - 7}{3}

11 a^{2} + 12 a = 15

- x^{2} - 8 = 0

0.004 y^{2} - 0.01 y + 121 = 50

60 + \frac{1}{2} ((a - 200) (5 - \frac{a}{40})) = 0

\frac{1}{4} a^{2 n} = x^{2}

What are the solutions to the equation 3t^2-10t+6=0 ?
The solutions to the equation 3t^2-10t+6=0 are t=(5+sqrt(7))/3 ,t=(5-sqrt(7))/3
Find the zeros of 3t^2-10t+6=0
The zeros of 3t^2-10t+6=0 are t=(5+sqrt(7))/3 ,t=(5-sqrt(7))/3