What are the solutions to the equation 60+1/2 ((a-200)(5-a/(40)))=0 ?

The solutions to the equation 60+1/2 ((a-200)(5-a/(40)))=0 are a=20(10-2sqrt(3)),a=20(10+2sqrt(3))

Find the zeros of 60+1/2 ((a-200)(5-a/(40)))=0

The zeros of 60+1/2 ((a-200)(5-a/(40)))=0 are a=20(10-2sqrt(3)),a=20(10+2sqrt(3))

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60 + \frac{1}{2} ((a - 200) (5 - \frac{a}{40})) = 0

a = 20 (10 - 23), a = 20 (10 + 23)

Decimal Notation

a = 130.71796 \dots, a = 269.28203 \dots

Solution steps

60 + \frac{1}{2} ((a - 200) (5 - \frac{a}{40})) = 0

Multiply both sides by

2

120 + (a - 200) (5 - \frac{a}{40}) = 0

Expand

120 + (a - 200) (5 - \frac{a}{40}) : - \frac{a ^{2}}{40} + 10 a - 880

- \frac{a ^{2}}{40} + 10 a - 880 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - \frac{1}{40} ) ( - 880 )}{2 ( - \frac{1}{40} )}

1 0^{2} - 4 (- \frac{1}{40}) (- 880) = 23

a_{1, 2} = \frac{- 10 \pm 2 3}{2 ( - \frac{1}{40} )}

Separate the solutions

a_{1} = \frac{- 10 + 2 3}{2 ( - \frac{1}{40} )}, a_{2} = \frac{- 10 - 2 3}{2 ( - \frac{1}{40} )}

a = \frac{- 10 + 2 3}{2 ( - \frac{1}{40} )} : 20 (10 - 23)

a = \frac{- 10 - 2 3}{2 ( - \frac{1}{40} )} : 20 (10 + 23)

The solutions to the quadratic equation are:

a = 20 (10 - 23), a = 20 (10 + 23)

\frac{1}{4} a^{2 n} = x^{2}

(3 x + 7)^{2} = 22

c (c + 2) = 0

x^{2} + 18 x + 120 = 0

3 Q^{2} - 192 Q + 3500 = 0

What are the solutions to the equation 60+1/2 ((a-200)(5-a/(40)))=0 ?
The solutions to the equation 60+1/2 ((a-200)(5-a/(40)))=0 are a=20(10-2sqrt(3)),a=20(10+2sqrt(3))
Find the zeros of 60+1/2 ((a-200)(5-a/(40)))=0
The zeros of 60+1/2 ((a-200)(5-a/(40)))=0 are a=20(10-2sqrt(3)),a=20(10+2sqrt(3))