What are the solutions to the equation x^2+18x+120=0 ?

The solutions to the equation x^2+18x+120=0 are x=-9+sqrt(39)i,x=-9-sqrt(39)i

Find the zeros of x^2+18x+120=0

The zeros of x^2+18x+120=0 are x=-9+sqrt(39)i,x=-9-sqrt(39)i

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x^{2} + 18 x + 120 = 0

x = - 9 + 39 i, x = - 9 - 39 i

Solution steps

x^{2} + 18 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 120}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 120 : 239 i

x_{1, 2} = \frac{- 18 \pm 2 39 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 39 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 39 i}{2 \cdot 1}

x = \frac{- 18 + 2 39 i}{2 \cdot 1} : - 9 + 39 i

x = \frac{- 18 - 2 39 i}{2 \cdot 1} : - 9 - 39 i

The solutions to the quadratic equation are:

x = - 9 + 39 i, x = - 9 - 39 i

3 Q^{2} - 192 Q + 3500 = 0

20 x^{2} - 130 x = - 200

3 x^{2} + x + 1

3 x^{2} + x - 2

- 7 x^{2} - 2 x = 1

What are the solutions to the equation x^2+18x+120=0 ?
The solutions to the equation x^2+18x+120=0 are x=-9+sqrt(39)i,x=-9-sqrt(39)i
Find the zeros of x^2+18x+120=0
The zeros of x^2+18x+120=0 are x=-9+sqrt(39)i,x=-9-sqrt(39)i