What are the solutions to the equation x^2+6x-4=x+2 ?

The solutions to the equation x^2+6x-4=x+2 are x=1,x=-6

Find the zeros of x^2+6x-4=x+2

The zeros of x^2+6x-4=x+2 are x=1,x=-6

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x^{2} + 6 x - 4 = x + 2

x = 1, x = - 6

Solution steps

x^{2} + 6 x - 4 = x + 2

Move

2

to the left side

x^{2} + 6 x - 6 = x

Move

x

to the left side

x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 1}, x_{2} = \frac{- 5 - 7}{2 \cdot 1}

x = \frac{- 5 + 7}{2 \cdot 1} : 1

x = \frac{- 5 - 7}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

p^{2} + 4 p + 6 = 0

x, x^{2} + \frac{k}{m} x = 0

r, x^{2} r^{2} - 3 x r + 3 = 0

0 = 255 - 21 t - 16 t^{2}

r, r^{2} - 1 = 0

What are the solutions to the equation x^2+6x-4=x+2 ?
The solutions to the equation x^2+6x-4=x+2 are x=1,x=-6
Find the zeros of x^2+6x-4=x+2
The zeros of x^2+6x-4=x+2 are x=1,x=-6