What are the solutions to the equation -6=x^2-x-6 ?

The solutions to the equation -6=x^2-x-6 are x=1,x=0

Find the zeros of -6=x^2-x-6

The zeros of -6=x^2-x-6 are x=1,x=0

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- 6 = x^{2} - x - 6

x = 1, x = 0

Solution steps

- 6 = x^{2} - x - 6

Switch sides

x^{2} - x - 6 = - 6

Move

6

to the left side

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x, x^{2} - 2 x = y^{2} - 2 y

(5 x + 2)^{2} = 100

0.5 x^{2} + 15 x + 5000 = 0

9 b^{2} + 18 b - 56 = 0

3 x^{2} - \frac{3}{2} x = \frac{1}{3}

What are the solutions to the equation -6=x^2-x-6 ?
The solutions to the equation -6=x^2-x-6 are x=1,x=0
Find the zeros of -6=x^2-x-6
The zeros of -6=x^2-x-6 are x=1,x=0