What are the solutions to the equation 5x^2-24x+28=0 ?

The solutions to the equation 5x^2-24x+28=0 are x= 14/5 ,x=2

Find the zeros of 5x^2-24x+28=0

The zeros of 5x^2-24x+28=0 are x= 14/5 ,x=2

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5 x^{2} - 24 x + 28 = 0

x = \frac{14}{5}, x = 2

Decimal Notation

x = 2.8, x = 2

Solution steps

5 x^{2} - 24 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 5 \cdot 28}{2 \cdot 5}

(- 24)^{2} - 4 \cdot 5 \cdot 28 = 4

x_{1, 2} = \frac{- ( - 24 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 24 ) - 4}{2 \cdot 5}

x = \frac{- ( - 24 ) + 4}{2 \cdot 5} : \frac{14}{5}

x = \frac{- ( - 24 ) - 4}{2 \cdot 5} : 2

The solutions to the quadratic equation are:

x = \frac{14}{5}, x = 2

1 + 2 + 3 + 4 + n = \frac{n ( n + 1 )}{2}

4 + y^{2} = 8 + 4 y

x^{2} + 23 x - 24 = 0

400 = 6 Q^{2} - 150 Q + 1000

(x - 10) (x) = 600

What are the solutions to the equation 5x^2-24x+28=0 ?
The solutions to the equation 5x^2-24x+28=0 are x= 14/5 ,x=2
Find the zeros of 5x^2-24x+28=0
The zeros of 5x^2-24x+28=0 are x= 14/5 ,x=2