What are the solutions to the equation 5x^2+7x-3=-x^2 ?

The solutions to the equation 5x^2+7x-3=-x^2 are x= 1/3 ,x=-3/2

Find the zeros of 5x^2+7x-3=-x^2

The zeros of 5x^2+7x-3=-x^2 are x= 1/3 ,x=-3/2

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5 x^{2} + 7 x - 3 = - x^{2}

x = \frac{1}{3}, x = - \frac{3}{2}

Decimal Notation

x = 0.33333 \dots, x = - 1.5

Solution steps

5 x^{2} + 7 x - 3 = - x^{2}

Move

x^{2}

to the left side

6 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 3) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 6}, x_{2} = \frac{- 7 - 11}{2 \cdot 6}

x = \frac{- 7 + 11}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 7 - 11}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{3}{2}

(x + 5)^{2} + 12 = 76

2 x^{2} + 6 + 4 = 0

x, z^{2} = y^{2} + x^{2}

12 x^{2} - 5 = - 3

- 3 (x + 1)^{2} + 5 = 0

What are the solutions to the equation 5x^2+7x-3=-x^2 ?
The solutions to the equation 5x^2+7x-3=-x^2 are x= 1/3 ,x=-3/2
Find the zeros of 5x^2+7x-3=-x^2
The zeros of 5x^2+7x-3=-x^2 are x= 1/3 ,x=-3/2