What are the solutions to the equation 3-x=3-x^2 ?

The solutions to the equation 3-x=3-x^2 are x=0,x=1

Find the zeros of 3-x=3-x^2

The zeros of 3-x=3-x^2 are x=0,x=1

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3 - x = 3 - x^{2}

x = 0, x = 1

Solution steps

3 - x = 3 - x^{2}

Switch sides

3 - x^{2} = 3 - x

Move

x

to the left side

3 - x^{2} + x = 3

Move

3

to the left side

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

x^{2} + 9 x + c

x, 3 x^{2} + 10 x - 5 = 0

4 x^{2} - 32 x = - 60

x^{2} + 625 = 0

7 v^{2} + 49 = 105

What are the solutions to the equation 3-x=3-x^2 ?
The solutions to the equation 3-x=3-x^2 are x=0,x=1
Find the zeros of 3-x=3-x^2
The zeros of 3-x=3-x^2 are x=0,x=1