What are the solutions to the equation 7v^2+49=105 ?

The solutions to the equation 7v^2+49=105 are v=2sqrt(2),v=-2sqrt(2)

Find the zeros of 7v^2+49=105

The zeros of 7v^2+49=105 are v=2sqrt(2),v=-2sqrt(2)

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7 v^{2} + 49 = 105

v = 22, v = - 22

Decimal Notation

v = 2.82842 \dots, v = - 2.82842 \dots

Solution steps

7 v^{2} + 49 = 105

Move

49

to the right side

7 v^{2} = 56

Divide both sides by

7

v^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 8, v = - 8

8 = 22

- 8 = - 22

v = 22, v = - 22

x, f = (2 x - 3 y)^{2}

x (x + 8) = 9

7 a^{2} + 2 a = 5

x^{2} + 12 x + 35 = 0

(4 - x) (- 1 - x) - 6 = 0

What are the solutions to the equation 7v^2+49=105 ?
The solutions to the equation 7v^2+49=105 are v=2sqrt(2),v=-2sqrt(2)
Find the zeros of 7v^2+49=105
The zeros of 7v^2+49=105 are v=2sqrt(2),v=-2sqrt(2)