What are the solutions to the equation 7a^2+2a=5 ?

The solutions to the equation 7a^2+2a=5 are a= 5/7 ,a=-1

Find the zeros of 7a^2+2a=5

The zeros of 7a^2+2a=5 are a= 5/7 ,a=-1

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7 a^{2} + 2 a = 5

a = \frac{5}{7}, a = - 1

Decimal Notation

a = 0.71428 \dots, a = - 1

Solution steps

7 a^{2} + 2 a = 5

Move

5

to the left side

7 a^{2} + 2 a - 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 ( - 5 )}{2 \cdot 7}

2^{2} - 4 \cdot 7 (- 5) = 12

a_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 7}

Separate the solutions

a_{1} = \frac{- 2 + 12}{2 \cdot 7}, a_{2} = \frac{- 2 - 12}{2 \cdot 7}

a = \frac{- 2 + 12}{2 \cdot 7} : \frac{5}{7}

a = \frac{- 2 - 12}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

a = \frac{5}{7}, a = - 1

x^{2} + 12 x + 35 = 0

(4 - x) (- 1 - x) - 6 = 0

2 x^{2} - 12 x - 224 = 0

- 7 z^{2} - 56 z

x^{2} + 50 x + 2600 = 0

What are the solutions to the equation 7a^2+2a=5 ?
The solutions to the equation 7a^2+2a=5 are a= 5/7 ,a=-1
Find the zeros of 7a^2+2a=5
The zeros of 7a^2+2a=5 are a= 5/7 ,a=-1