What are the solutions to the equation (4-x)(-1-x)-6=0 ?

The solutions to the equation (4-x)(-1-x)-6=0 are x=5,x=-2

Find the zeros of (4-x)(-1-x)-6=0

The zeros of (4-x)(-1-x)-6=0 are x=5,x=-2

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(4 - x) (- 1 - x) - 6 = 0

x = 5, x = - 2

Solution steps

(4 - x) (- 1 - x) - 6 = 0

Expand

(4 - x) (- 1 - x) - 6 : x^{2} - 3 x - 10

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

2 x^{2} - 12 x - 224 = 0

- 7 z^{2} - 56 z

x^{2} + 50 x + 2600 = 0

x, e x = d (x^{2} - g)

1 0^{2} + x^{2} = 2 5^{2}

What are the solutions to the equation (4-x)(-1-x)-6=0 ?
The solutions to the equation (4-x)(-1-x)-6=0 are x=5,x=-2
Find the zeros of (4-x)(-1-x)-6=0
The zeros of (4-x)(-1-x)-6=0 are x=5,x=-2