What are the solutions to the equation 10^2+x^2=25^2 ?

The solutions to the equation 10^2+x^2=25^2 are x=5sqrt(21),x=-5sqrt(21)

Find the zeros of 10^2+x^2=25^2

The zeros of 10^2+x^2=25^2 are x=5sqrt(21),x=-5sqrt(21)

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1 0^{2} + x^{2} = 2 5^{2}

x = 521, x = - 521

Decimal Notation

x = 22.91287 \dots, x = - 22.91287 \dots

Solution steps

1 0^{2} + x^{2} = 2 5^{2}

Move

1 0^{2}

to the right side

x^{2} = 525

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 525, x = - 525

525 = 521

- 525 = - 521

x = 521, x = - 521

6 x^{2} - 7 x = 20

x, x^{2} + y^{2} - 8 x + 27 - 8 = 0

x^{2} + 4 - 2 x = 0

x^{2} + x - 6 = 6

a, x^{2} + (y - a)^{2} = 25

What are the solutions to the equation 10^2+x^2=25^2 ?
The solutions to the equation 10^2+x^2=25^2 are x=5sqrt(21),x=-5sqrt(21)
Find the zeros of 10^2+x^2=25^2
The zeros of 10^2+x^2=25^2 are x=5sqrt(21),x=-5sqrt(21)