What are the solutions to the equation solvefor a,x^2+(y-a)^2=25 ?

The solutions to the equation solvefor a,x^2+(y-a)^2=25 are a=-sqrt(25-x^2)+y,a=sqrt(25-x^2)+y

Find the zeros of solvefor a,x^2+(y-a)^2=25

The zeros of solvefor a,x^2+(y-a)^2=25 are a=-sqrt(25-x^2)+y,a=sqrt(25-x^2)+y

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solve for

a, x^{2} + (y - a)^{2} = 25

a = - 25 - x^{2} + y, a = 25 - x^{2} + y

Solution steps

x^{2} + (y - a)^{2} = 25

Move

x^{2}

to the right side

(y - a)^{2} = 25 - x^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - a = 25 - x^{2} : a = - 25 - x^{2} + y

Solve

y - a = - 25 - x^{2} : a = 25 - x^{2} + y

The solutions to the quadratic equation are:

a = - 25 - x^{2} + y, a = 25 - x^{2} + y

x, x^{2} - 4 x = - 4

n^{2} + 4 n = 32

12 x^{2} - 12 x - 2 = 0

x^{2} + 3 x = 108

x, f = x^{2} + y^{2} + 2 x y

What are the solutions to the equation solvefor a,x^2+(y-a)^2=25 ?
The solutions to the equation solvefor a,x^2+(y-a)^2=25 are a=-sqrt(25-x^2)+y,a=sqrt(25-x^2)+y
Find the zeros of solvefor a,x^2+(y-a)^2=25
The zeros of solvefor a,x^2+(y-a)^2=25 are a=-sqrt(25-x^2)+y,a=sqrt(25-x^2)+y