What are the solutions to the equation 3r^2-1=-16 ?

The solutions to the equation 3r^2-1=-16 are r=sqrt(5)i,r=-sqrt(5)i

Find the zeros of 3r^2-1=-16

The zeros of 3r^2-1=-16 are r=sqrt(5)i,r=-sqrt(5)i

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3 r^{2} - 1 = - 16

r = 5 i, r = - 5 i

Solution steps

3 r^{2} - 1 = - 16

Move

1

to the right side

3 r^{2} = - 15

Divide both sides by

3

r^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 5, r = - - 5

- 5 = 5 i

- - 5 = - 5 i

r = 5 i, r = - 5 i

- x (x + 3) 2 = - 5 (x + 8)

x^{2} - 10 x + 44

5 x^{2} - 2 x = 0

2 m^{2} - 3 m - 2 = 0

0 = 9 x^{2} - 25

What are the solutions to the equation 3r^2-1=-16 ?
The solutions to the equation 3r^2-1=-16 are r=sqrt(5)i,r=-sqrt(5)i
Find the zeros of 3r^2-1=-16
The zeros of 3r^2-1=-16 are r=sqrt(5)i,r=-sqrt(5)i