What are the solutions to the equation x^2-3x-26=2 ?

The solutions to the equation x^2-3x-26=2 are x=7,x=-4

Find the zeros of x^2-3x-26=2

The zeros of x^2-3x-26=2 are x=7,x=-4

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x^{2} - 3 x - 26 = 2

x = 7, x = - 4

Solution steps

x^{2} - 3 x - 26 = 2

Move

2

to the left side

x^{2} - 3 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

x = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

x = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 7, x = - 4

x, y^{3} + 3 x^{2} y = c_{1}

8 x^{2} + 7 x - 1666 = 0

2 X^{2} + 8 X + 6 = 0

5 = - 0.01 x^{2} - 0.4 x + 10

r, A = π (r^{2} - r^{2})

What are the solutions to the equation x^2-3x-26=2 ?
The solutions to the equation x^2-3x-26=2 are x=7,x=-4
Find the zeros of x^2-3x-26=2
The zeros of x^2-3x-26=2 are x=7,x=-4