What are the solutions to the equation 5=-0.01x^2-0.4x+10 ?

The solutions to the equation 5=-0.01x^2-0.4x+10 are x=-50,x=10

Find the zeros of 5=-0.01x^2-0.4x+10

The zeros of 5=-0.01x^2-0.4x+10 are x=-50,x=10

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5 = - 0.01 x^{2} - 0.4 x + 10

x = - 50, x = 10

Solution steps

5 = - 0.01 x^{2} - 0.4 x + 10

Multiply both sides by

100

500 = - x^{2} - 40 x + 1000

Switch sides

- x^{2} - 40 x + 1000 = 500

Move

500

to the left side

- x^{2} - 40 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 ( - 1 ) \cdot 500}{2 ( - 1 )}

(- 40)^{2} - 4 (- 1) \cdot 500 = 60

x_{1, 2} = \frac{- ( - 40 ) \pm 60}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 60}{2 ( - 1 )}, x_{2} = \frac{- ( - 40 ) - 60}{2 ( - 1 )}

x = \frac{- ( - 40 ) + 60}{2 ( - 1 )} : - 50

x = \frac{- ( - 40 ) - 60}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = - 50, x = 10

r, A = π (r^{2} - r^{2})

x^{2} - 12 x - 10 = 0

5 x^{2} + 24 x = 0

(x - 5)^{2} - 10 (x - 5) = 24

\frac{7 x ^{2}}{2} = 27.7778

What are the solutions to the equation 5=-0.01x^2-0.4x+10 ?
The solutions to the equation 5=-0.01x^2-0.4x+10 are x=-50,x=10
Find the zeros of 5=-0.01x^2-0.4x+10
The zeros of 5=-0.01x^2-0.4x+10 are x=-50,x=10