What are the solutions to the equation (x-5)^2-10(x-5)=24 ?

The solutions to the equation (x-5)^2-10(x-5)=24 are x=17,x=3

Find the zeros of (x-5)^2-10(x-5)=24

The zeros of (x-5)^2-10(x-5)=24 are x=17,x=3

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(x - 5)^{2} - 10 (x - 5) = 24

x = 17, x = 3

Solution steps

(x - 5)^{2} - 10 (x - 5) = 24

Expand

(x - 5)^{2} - 10 (x - 5) : x^{2} - 20 x + 75

x^{2} - 20 x + 75 = 24

Move

24

to the left side

x^{2} - 20 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 51}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 51 = 14

x_{1, 2} = \frac{- ( - 20 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 14}{2 \cdot 1}

x = \frac{- ( - 20 ) + 14}{2 \cdot 1} : 17

x = \frac{- ( - 20 ) - 14}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 17, x = 3

\frac{7 x ^{2}}{2} = 27.7778

4 (x^{2} + x - 2) = x + 2

m^{2} - 18 m + 81 = 0

4 x^{2} = - 5 x + 6

- x^{2} - 8 x - 2 = x + 7

What are the solutions to the equation (x-5)^2-10(x-5)=24 ?
The solutions to the equation (x-5)^2-10(x-5)=24 are x=17,x=3
Find the zeros of (x-5)^2-10(x-5)=24
The zeros of (x-5)^2-10(x-5)=24 are x=17,x=3