What are the solutions to the equation -x^2-8x-2=x+7 ?

The solutions to the equation -x^2-8x-2=x+7 are x=-(9+3sqrt(5))/2 ,x=-(9-3sqrt(5))/2

Find the zeros of -x^2-8x-2=x+7

The zeros of -x^2-8x-2=x+7 are x=-(9+3sqrt(5))/2 ,x=-(9-3sqrt(5))/2

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- x^{2} - 8 x - 2 = x + 7

x = - \frac{9 + 3 5}{2}, x = - \frac{9 - 3 5}{2}

Decimal Notation

x = - 7.85410 \dots, x = - 1.14589 \dots

Solution steps

- x^{2} - 8 x - 2 = x + 7

Move

7

to the left side

- x^{2} - 8 x - 9 = x

Move

x

to the left side

- x^{2} - 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) (- 9) = 35

x_{1, 2} = \frac{- ( - 9 ) \pm 3 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 9 ) - 3 5}{2 ( - 1 )}

x = \frac{- ( - 9 ) + 3 5}{2 ( - 1 )} : - \frac{9 + 3 5}{2}

x = \frac{- ( - 9 ) - 3 5}{2 ( - 1 )} : - \frac{9 - 3 5}{2}

The solutions to the quadratic equation are:

x = - \frac{9 + 3 5}{2}, x = - \frac{9 - 3 5}{2}

x^{2} + (2 + 5) x + 25 = 0

y^{2} = \frac{3}{4} y - \frac{1}{8}

2 x + 19 = x^{2} + 4 x + 4

m^{2} + 9 m + 18 = 0

3 z^{2} + 1 = 0

What are the solutions to the equation -x^2-8x-2=x+7 ?
The solutions to the equation -x^2-8x-2=x+7 are x=-(9+3sqrt(5))/2 ,x=-(9-3sqrt(5))/2
Find the zeros of -x^2-8x-2=x+7
The zeros of -x^2-8x-2=x+7 are x=-(9+3sqrt(5))/2 ,x=-(9-3sqrt(5))/2