What are the solutions to the equation quadraticformula-t^2+6t-9=0 ?

The solutions to the equation quadraticformula-t^2+6t-9=0 are t=3

Find the zeros of quadraticformula-t^2+6t-9=0

The zeros of quadraticformula-t^2+6t-9=0 are t=3

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- t^{2} + 6 t - 9 = 0

t = 3

Solution steps

- t^{2} + 6 t - 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 9) = 0

t_{1, 2} = \frac{- 6 \pm 0}{2 ( - 1 )}

t = \frac{- 6}{2 ( - 1 )}

\frac{- 6}{2 ( - 1 )} = 3

t = 3

The solution to the quadratic equation is:

t = 3

120 w^{2} + 1800 w - 4080 = 0

t, - 0.8 t^{2} + 32 t = 0

- 4.9 x^{2} - 3 x + 30

5 x^{2} + 30 x + 45 = 0

y^{2} - 5 y = 2 y

What are the solutions to the equation quadraticformula-t^2+6t-9=0 ?
The solutions to the equation quadraticformula-t^2+6t-9=0 are t=3
Find the zeros of quadraticformula-t^2+6t-9=0
The zeros of quadraticformula-t^2+6t-9=0 are t=3