What are the solutions to the equation 6x^2-2=7x ?

The solutions to the equation 6x^2-2=7x are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

Find the zeros of 6x^2-2=7x

The zeros of 6x^2-2=7x are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)

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6 x^{2} - 2 = 7 x

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

Decimal Notation

x = 1.40407 \dots, x = - 0.23740 \dots

Solution steps

6 x^{2} - 2 = 7 x

Move

7 x

to the left side

6 x^{2} - 2 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 2) = 97

x_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 6}

x = \frac{- ( - 7 ) + 97}{2 \cdot 6} : \frac{7 + 97}{12}

x = \frac{- ( - 7 ) - 97}{2 \cdot 6} : \frac{7 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{7 + 97}{12}, x = \frac{7 - 97}{12}

2 x^{2} - 16 x + 16 = - 10 + 16

2.5 x^{2} + 25 x - 240 = 0

m^{2} - 12 m = 0

4 x^{2} - 13 x + 9 = 0

y^{1} = y^{2}

What are the solutions to the equation 6x^2-2=7x ?
The solutions to the equation 6x^2-2=7x are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)
Find the zeros of 6x^2-2=7x
The zeros of 6x^2-2=7x are x=(7+sqrt(97))/(12),x=(7-sqrt(97))/(12)