What are the solutions to the equation 0=-x^2+10x-16 ?

The solutions to the equation 0=-x^2+10x-16 are x=2,x=8

Find the zeros of 0=-x^2+10x-16

The zeros of 0=-x^2+10x-16 are x=2,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = - x^{2} + 10 x - 16

x = 2, x = 8

Solution steps

0 = - x^{2} + 10 x - 16

Switch sides

- x^{2} + 10 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 16 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 16) = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 ( - 1 )}, x_{2} = \frac{- 10 - 6}{2 ( - 1 )}

x = \frac{- 10 + 6}{2 ( - 1 )} : 2

x = \frac{- 10 - 6}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 2, x = 8

12 x^{2} - 476 x + 3160 = 0

18 a^{2} - 30 = - 33 a

- 2 x^{2} + 12 x - 5 = 0

x^{2} - \frac{3}{2} x = \frac{7}{16}

1 4^{2} + x^{2} = 5 0^{2}

What are the solutions to the equation 0=-x^2+10x-16 ?
The solutions to the equation 0=-x^2+10x-16 are x=2,x=8
Find the zeros of 0=-x^2+10x-16
The zeros of 0=-x^2+10x-16 are x=2,x=8