What are the solutions to the equation 3x^2-20x+21=0 ?

The solutions to the equation 3x^2-20x+21=0 are x=(10+sqrt(37))/3 ,x=(10-sqrt(37))/3

Find the zeros of 3x^2-20x+21=0

The zeros of 3x^2-20x+21=0 are x=(10+sqrt(37))/3 ,x=(10-sqrt(37))/3

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3 x^{2} - 20 x + 21 = 0

x = \frac{10 + 37}{3}, x = \frac{10 - 37}{3}

Decimal Notation

x = 5.36092 \dots, x = 1.30574 \dots

Solution steps

3 x^{2} - 20 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 3 \cdot 21}{2 \cdot 3}

(- 20)^{2} - 4 \cdot 3 \cdot 21 = 237

x_{1, 2} = \frac{- ( - 20 ) \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 37}{2 \cdot 3}, x_{2} = \frac{- ( - 20 ) - 2 37}{2 \cdot 3}

x = \frac{- ( - 20 ) + 2 37}{2 \cdot 3} : \frac{10 + 37}{3}

x = \frac{- ( - 20 ) - 2 37}{2 \cdot 3} : \frac{10 - 37}{3}

The solutions to the quadratic equation are:

x = \frac{10 + 37}{3}, x = \frac{10 - 37}{3}

12 x^{2} + 54 x - 30 = 0

x^{2} + 2 \cdot x + 5 = 0

x^{2} + \frac{4}{5} x = - \frac{1}{5}

16 x^{2} - 256 = 0

0.003 x^{2} - 0.04 x + 2 - a = 0

What are the solutions to the equation 3x^2-20x+21=0 ?
The solutions to the equation 3x^2-20x+21=0 are x=(10+sqrt(37))/3 ,x=(10-sqrt(37))/3
Find the zeros of 3x^2-20x+21=0
The zeros of 3x^2-20x+21=0 are x=(10+sqrt(37))/3 ,x=(10-sqrt(37))/3