What are the solutions to the equation n^2=10+3n ?

The solutions to the equation n^2=10+3n are n=5,n=-2

Find the zeros of n^2=10+3n

The zeros of n^2=10+3n are n=5,n=-2

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n^{2} = 10 + 3 n

n = 5, n = - 2

Solution steps

n^{2} = 10 + 3 n

Move

3 n

to the left side

n^{2} - 3 n = 10

Move

10

to the left side

n^{2} - 3 n - 10 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

n_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

n = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

n = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

n = 5, n = - 2

2 x - \frac{1}{2} x^{2} = 0

- 8 x^{2} - 12 (- 2) + C = 0

4 x^{2} - 6 x + 8 = 0

w^{2} - 2 w + 5 = 0

8 x^{2} + 8 = 16

What are the solutions to the equation n^2=10+3n ?
The solutions to the equation n^2=10+3n are n=5,n=-2
Find the zeros of n^2=10+3n
The zeros of n^2=10+3n are n=5,n=-2