What are the solutions to the equation w^2-2w+5=0 ?

The solutions to the equation w^2-2w+5=0 are w=1+2i,w=1-2i

Find the zeros of w^2-2w+5=0

The zeros of w^2-2w+5=0 are w=1+2i,w=1-2i

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w^{2} - 2 w + 5 = 0

w = 1 + 2 i, w = 1 - 2 i

Solution steps

w^{2} - 2 w + 5 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

w_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, w_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

w = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

w = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

w = 1 + 2 i, w = 1 - 2 i

8 x^{2} + 8 = 16

- x^{2} + 3 x + 7 = x^{2} + 9 x + 7

7 x^{2} - 23 x + 6 = 0

12 x^{2} - 11 x + 2 = 0

10 r^{2} - 2 r - 18 = 0

What are the solutions to the equation w^2-2w+5=0 ?
The solutions to the equation w^2-2w+5=0 are w=1+2i,w=1-2i
Find the zeros of w^2-2w+5=0
The zeros of w^2-2w+5=0 are w=1+2i,w=1-2i