What are the solutions to the equation x(x+2)=80 ?

The solutions to the equation x(x+2)=80 are x=8,x=-10

Find the zeros of x(x+2)=80

The zeros of x(x+2)=80 are x=8,x=-10

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x (x + 2) = 80

x = 8, x = - 10

Solution steps

x (x + 2) = 80

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 80

Move

80

to the left side

x^{2} + 2 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 1}, x_{2} = \frac{- 2 - 18}{2 \cdot 1}

x = \frac{- 2 + 18}{2 \cdot 1} : 8

x = \frac{- 2 - 18}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

t^{2} - 9 t = 0

x, 16 x^{2} + 24 x y + 9 y^{2} - 15 x + 20 y - 25 = 0

x^{2} - 18 x + 65 = 0

x^{2} + x - e = 0

2 x^{2} - 6 x = 6 \cdot 2 - 8 x

What are the solutions to the equation x(x+2)=80 ?
The solutions to the equation x(x+2)=80 are x=8,x=-10
Find the zeros of x(x+2)=80
The zeros of x(x+2)=80 are x=8,x=-10