What are the solutions to the equation t^2-9t=0 ?

The solutions to the equation t^2-9t=0 are t=9,t=0

Find the zeros of t^2-9t=0

The zeros of t^2-9t=0 are t=9,t=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^{2} - 9 t = 0

t = 9, t = 0

Solution steps

t^{2} - 9 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 0 = 9

t_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 1}, t_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 1}

t = \frac{- ( - 9 ) + 9}{2 \cdot 1} : 9

t = \frac{- ( - 9 ) - 9}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 9, t = 0

x, 16 x^{2} + 24 x y + 9 y^{2} - 15 x + 20 y - 25 = 0

x^{2} - 18 x + 65 = 0

x^{2} + x - e = 0

2 x^{2} - 6 x = 6 \cdot 2 - 8 x

6 x^{2} + 24 \times 18 = 0

What are the solutions to the equation t^2-9t=0 ?
The solutions to the equation t^2-9t=0 are t=9,t=0
Find the zeros of t^2-9t=0
The zeros of t^2-9t=0 are t=9,t=0