What are the solutions to the equation 6x^2+24\times 18=0 ?

The solutions to the equation 6x^2+24\times 18=0 are x=6sqrt(2)i,x=-6sqrt(2)i

Find the zeros of 6x^2+24\times 18=0

The zeros of 6x^2+24\times 18=0 are x=6sqrt(2)i,x=-6sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 24 \cdot 18 = 0

x = 62 i, x = - 62 i

Solution steps

6 x^{2} + 24 \cdot 18 = 0

Move

24 \cdot 18

to the right side

6 x^{2} = - 432

Divide both sides by

6

x^{2} = - 72

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 72, x = - - 72

- 72 = 62 i

- - 72 = - 62 i

x = 62 i, x = - 62 i

y, z = \frac{y ^{2}}{4}

\frac{1}{3} v^{2} + 27 = 12

20 x^{2} - 33 x + 7 = 0

6 x^{2} - 40 = x

12 - b - b^{2} = 0

What are the solutions to the equation 6x^2+24\times 18=0 ?
The solutions to the equation 6x^2+24\times 18=0 are x=6sqrt(2)i,x=-6sqrt(2)i
Find the zeros of 6x^2+24\times 18=0
The zeros of 6x^2+24\times 18=0 are x=6sqrt(2)i,x=-6sqrt(2)i