What are the solutions to the equation 1/3 v^2+27=12 ?

The solutions to the equation 1/3 v^2+27=12 are v=3sqrt(5)i,v=-3sqrt(5)i

Find the zeros of 1/3 v^2+27=12

The zeros of 1/3 v^2+27=12 are v=3sqrt(5)i,v=-3sqrt(5)i

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\frac{1}{3} v^{2} + 27 = 12

v = 35 i, v = - 35 i

Solution steps

\frac{1}{3} v^{2} + 27 = 12

Move

27

to the right side

\frac{1}{3} v^{2} = - 15

Multiply both sides by

3

v^{2} = - 45

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = - 45, v = - - 45

- 45 = 35 i

- - 45 = - 35 i

v = 35 i, v = - 35 i

20 x^{2} - 33 x + 7 = 0

6 x^{2} - 40 = x

12 - b - b^{2} = 0

x (x + 1) = 110

m^{2} - 8 m + 7 = 0

What are the solutions to the equation 1/3 v^2+27=12 ?
The solutions to the equation 1/3 v^2+27=12 are v=3sqrt(5)i,v=-3sqrt(5)i
Find the zeros of 1/3 v^2+27=12
The zeros of 1/3 v^2+27=12 are v=3sqrt(5)i,v=-3sqrt(5)i