What are the solutions to the equation 2x^2+1=19 ?

The solutions to the equation 2x^2+1=19 are x=3,x=-3

Find the zeros of 2x^2+1=19

The zeros of 2x^2+1=19 are x=3,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 1 = 19

x = 3, x = - 3

Solution steps

2 x^{2} + 1 = 19

Move

1

to the right side

2 x^{2} = 18

Divide both sides by

2

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

x^{2} - 6 x = 0

2 x^{2} + 1 = 8 x

5 x^{2} - 9 = 11 x

x, 3 x^{2} + 2 x + 2 = k x + k

x (13 - 4 x) = 0

What are the solutions to the equation 2x^2+1=19 ?
The solutions to the equation 2x^2+1=19 are x=3,x=-3
Find the zeros of 2x^2+1=19
The zeros of 2x^2+1=19 are x=3,x=-3