What are the solutions to the equation 5z^2+8z+5=0 ?

The solutions to the equation 5z^2+8z+5=0 are z=-4/5+i 3/5 ,z=-4/5-i 3/5

Find the zeros of 5z^2+8z+5=0

The zeros of 5z^2+8z+5=0 are z=-4/5+i 3/5 ,z=-4/5-i 3/5

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5 z^{2} + 8 z + 5 = 0

z = - \frac{4}{5} + i \frac{3}{5}, z = - \frac{4}{5} - i \frac{3}{5}

Solution steps

5 z^{2} + 8 z + 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

8^{2} - 4 \cdot 5 \cdot 5 : 6 i

z_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 8 + 6 i}{2 \cdot 5}, z_{2} = \frac{- 8 - 6 i}{2 \cdot 5}

z = \frac{- 8 + 6 i}{2 \cdot 5} : - \frac{4}{5} + i \frac{3}{5}

z = \frac{- 8 - 6 i}{2 \cdot 5} : - \frac{4}{5} - i \frac{3}{5}

The solutions to the quadratic equation are:

z = - \frac{4}{5} + i \frac{3}{5}, z = - \frac{4}{5} - i \frac{3}{5}

x^{2} - 7 x + 27 = 15

- x^{2} - 8 x + 20 = 0

(x - 1)^{2} = \frac{5}{9}

(3 x + 2)^{2} + 4 = (x + 1)^{2}

x, x^{2} - y^{2} + z^{2} = 0

What are the solutions to the equation 5z^2+8z+5=0 ?
The solutions to the equation 5z^2+8z+5=0 are z=-4/5+i 3/5 ,z=-4/5-i 3/5
Find the zeros of 5z^2+8z+5=0
The zeros of 5z^2+8z+5=0 are z=-4/5+i 3/5 ,z=-4/5-i 3/5