What are the solutions to the equation -x^2-8x+20=0 ?

The solutions to the equation -x^2-8x+20=0 are x=-10,x=2

Find the zeros of -x^2-8x+20=0

The zeros of -x^2-8x+20=0 are x=-10,x=2

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- x^{2} - 8 x + 20 = 0

x = - 10, x = 2

Solution steps

- x^{2} - 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) \cdot 20}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) \cdot 20 = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 12}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 12}{2 ( - 1 )} : - 10

x = \frac{- ( - 8 ) - 12}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 10, x = 2

(x - 1)^{2} = \frac{5}{9}

(3 x + 2)^{2} + 4 = (x + 1)^{2}

x, x^{2} - y^{2} + z^{2} = 0

t, f = (t - 5) e t - 5 U (t - 5)

2 (x + 5) = x^{2} + 5 x

What are the solutions to the equation -x^2-8x+20=0 ?
The solutions to the equation -x^2-8x+20=0 are x=-10,x=2
Find the zeros of -x^2-8x+20=0
The zeros of -x^2-8x+20=0 are x=-10,x=2