What are the solutions to the equation 2(x+5)=x^2+5x ?

The solutions to the equation 2(x+5)=x^2+5x are x=2,x=-5

Find the zeros of 2(x+5)=x^2+5x

The zeros of 2(x+5)=x^2+5x are x=2,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x + 5) = x^{2} + 5 x

x = 2, x = - 5

Solution steps

2 (x + 5) = x^{2} + 5 x

Expand

2 (x + 5) : 2 x + 10

2 x + 10 = x^{2} + 5 x

Switch sides

x^{2} + 5 x = 2 x + 10

Move

10

to the left side

x^{2} + 5 x - 10 = 2 x

Move

2 x

to the left side

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

v^{2} - 3 v - 18 = 0

t, u = t^{2} + 2

18 = 0.9 x^{2} - 3 x + 3

x^{2} + 4 x + 6 = 0

5 + 4 x - x^{2}

What are the solutions to the equation 2(x+5)=x^2+5x ?
The solutions to the equation 2(x+5)=x^2+5x are x=2,x=-5
Find the zeros of 2(x+5)=x^2+5x
The zeros of 2(x+5)=x^2+5x are x=2,x=-5