What are the solutions to the equation completesquare 5+4x-x^2 ?

The solutions to the equation completesquare 5+4x-x^2 are -(x-2)^2+9

Find the zeros of completesquare 5+4x-x^2

The zeros of completesquare 5+4x-x^2 are -(x-2)^2+9

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complete the square

5 + 4 x - x^{2}

- (x - 2)^{2} + 9

Solution steps

5 + 4 x - x^{2}

Write in the standard form

a x^{2} + b x + c

- x^{2} + 4 x + 5

Write

- x^{2} + 4 x + 5

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 4 x - 5)

2 a = - 4 : a = - 2

Add and subtract

(- 2)^{2}

- (x^{2} - 4 x - 5 + (- 2)^{2} - (- 2)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 4 x + (- 2)^{2} = (x - 2)^{2}

- ((x - 2)^{2} - 5 - (- 2)^{2})

Simplify

- (x - 2)^{2} + 9

x^{2} + (- x)^{2} = 1

2 (x - 3)^{2} = 0

A, C^{2} + 2 XB = A XB - A^{2}

3 x^{2} - 12 x + 28

\frac{1}{2} x^{2} - 50 = 0

What are the solutions to the equation completesquare 5+4x-x^2 ?
The solutions to the equation completesquare 5+4x-x^2 are -(x-2)^2+9
Find the zeros of completesquare 5+4x-x^2
The zeros of completesquare 5+4x-x^2 are -(x-2)^2+9