What are the solutions to the equation 3x^2+9x-7=0 ?

The solutions to the equation 3x^2+9x-7=0 are x=(-9+sqrt(165))/6 ,x=(-9-sqrt(165))/6

Find the zeros of 3x^2+9x-7=0

The zeros of 3x^2+9x-7=0 are x=(-9+sqrt(165))/6 ,x=(-9-sqrt(165))/6

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3 x^{2} + 9 x - 7 = 0

x = \frac{- 9 + 165}{6}, x = \frac{- 9 - 165}{6}

Decimal Notation

x = 0.64087 \dots, x = - 3.64087 \dots

Solution steps

3 x^{2} + 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 7) = 165

x_{1, 2} = \frac{- 9 \pm 165}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 165}{2 \cdot 3}, x_{2} = \frac{- 9 - 165}{2 \cdot 3}

x = \frac{- 9 + 165}{2 \cdot 3} : \frac{- 9 + 165}{6}

x = \frac{- 9 - 165}{2 \cdot 3} : \frac{- 9 - 165}{6}

The solutions to the quadratic equation are:

x = \frac{- 9 + 165}{6}, x = \frac{- 9 - 165}{6}

4 x^{2} - 8 x + 6

6 u^{2} + 30 u = 0

x^{2} = \frac{3}{25}

x^{2} + 8 x + 15 = 0

x^{2} + 12 x - 5

What are the solutions to the equation 3x^2+9x-7=0 ?
The solutions to the equation 3x^2+9x-7=0 are x=(-9+sqrt(165))/6 ,x=(-9-sqrt(165))/6
Find the zeros of 3x^2+9x-7=0
The zeros of 3x^2+9x-7=0 are x=(-9+sqrt(165))/6 ,x=(-9-sqrt(165))/6