What are the solutions to the equation quadraticformula x^2+8x+15=0 ?

The solutions to the equation quadraticformula x^2+8x+15=0 are x=-3,x=-5

Find the zeros of quadraticformula x^2+8x+15=0

The zeros of quadraticformula x^2+8x+15=0 are x=-3,x=-5

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x^{2} + 8 x + 15 = 0

x = - 3, x = - 5

Solution steps

x^{2} + 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 1}, x_{2} = \frac{- 8 - 2}{2 \cdot 1}

x = \frac{- 8 + 2}{2 \cdot 1} : - 3

x = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

x^{2} + 12 x - 5

9 x^{2} - 6 x = 1

x^{2} + 12 x + 7

a, a^{2} = h^{2} + (\frac{a}{2})^{2}

(x - 2)^{3} = x^{3} - 2 x

What are the solutions to the equation quadraticformula x^2+8x+15=0 ?
The solutions to the equation quadraticformula x^2+8x+15=0 are x=-3,x=-5
Find the zeros of quadraticformula x^2+8x+15=0
The zeros of quadraticformula x^2+8x+15=0 are x=-3,x=-5