What are the solutions to the equation solvefor a,a^2=h^2+(a/2)^2 ?

The solutions to the equation solvefor a,a^2=h^2+(a/2)^2 are a=(2h)/(sqrt(3)),a=-(2h)/(sqrt(3))

Find the zeros of solvefor a,a^2=h^2+(a/2)^2

The zeros of solvefor a,a^2=h^2+(a/2)^2 are a=(2h)/(sqrt(3)),a=-(2h)/(sqrt(3))

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solve for

a, a^{2} = h^{2} + (\frac{a}{2})^{2}

a = \frac{2 h}{3}, a = - \frac{2 h}{3}

Solution steps

a^{2} = h^{2} + (\frac{a}{2})^{2}

Expand

h^{2} + (\frac{a}{2})^{2} : h^{2} + \frac{a ^{2}}{4}

a^{2} = h^{2} + \frac{a ^{2}}{4}

Move

\frac{a ^{2}}{4}

to the left side

\frac{3 a ^{2}}{4} = h^{2}

Multiply both sides by

4

3 a^{2} = 4 h^{2}

Divide both sides by

3

a^{2} = \frac{4 h ^{2}}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{4 h ^{2}}{3}, a = - \frac{4 h ^{2}}{3}

Simplify

\frac{4 h ^{2}}{3} : \frac{2 h}{3}

Simplify

- \frac{4 h ^{2}}{3} : - \frac{2 h}{3}

a = \frac{2 h}{3}, a = - \frac{2 h}{3}

(x - 2)^{3} = x^{3} - 2 x

a, a^{2} + 2 b^{2} = 2 a - 1

x^{2} - 64 x = - 3 x^{2} + 16 x

x^{2} - 19 x + 9 = 0

4 x^{2} + 3 = 103

What are the solutions to the equation solvefor a,a^2=h^2+(a/2)^2 ?
The solutions to the equation solvefor a,a^2=h^2+(a/2)^2 are a=(2h)/(sqrt(3)),a=-(2h)/(sqrt(3))
Find the zeros of solvefor a,a^2=h^2+(a/2)^2
The zeros of solvefor a,a^2=h^2+(a/2)^2 are a=(2h)/(sqrt(3)),a=-(2h)/(sqrt(3))