What are the solutions to the equation 1x^2-1x-2=0 ?

The solutions to the equation 1x^2-1x-2=0 are x=2,x=-1

Find the zeros of 1x^2-1x-2=0

The zeros of 1x^2-1x-2=0 are x=2,x=-1

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1 x^{2} - 1 x - 2 = 0

x = 2, x = - 1

Solution steps

1 \cdot x^{2} - 1 \cdot x - 2 = 0

Refine

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

n^{2} - n - 5 = - 2 n^{2} - 2 n^{2}

(0.036 - x) (7.1 \times 1 0^{- 4}) = x^{2}

2 x^{2} + 16 x + 26 = 0

6 0^{2} + 8 0^{2} = x^{2}

x^{2} + 24 x + 150 = 0

What are the solutions to the equation 1x^2-1x-2=0 ?
The solutions to the equation 1x^2-1x-2=0 are x=2,x=-1
Find the zeros of 1x^2-1x-2=0
The zeros of 1x^2-1x-2=0 are x=2,x=-1