What are the solutions to the equation -2x^2+16x-31=0 ?

The solutions to the equation -2x^2+16x-31=0 are x=(8-sqrt(2))/2 ,x=(8+sqrt(2))/2

Find the zeros of -2x^2+16x-31=0

The zeros of -2x^2+16x-31=0 are x=(8-sqrt(2))/2 ,x=(8+sqrt(2))/2

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- 2 x^{2} + 16 x - 31 = 0

x = \frac{8 - 2}{2}, x = \frac{8 + 2}{2}

Decimal Notation

x = 3.29289 \dots, x = 4.70710 \dots

Solution steps

- 2 x^{2} + 16 x - 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) ( - 31 )}{2 ( - 2 )}

1 6^{2} - 4 (- 2) (- 31) = 22

x_{1, 2} = \frac{- 16 \pm 2 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 2 2}{2 ( - 2 )}, x_{2} = \frac{- 16 - 2 2}{2 ( - 2 )}

x = \frac{- 16 + 2 2}{2 ( - 2 )} : \frac{8 - 2}{2}

x = \frac{- 16 - 2 2}{2 ( - 2 )} : \frac{8 + 2}{2}

The solutions to the quadratic equation are:

x = \frac{8 - 2}{2}, x = \frac{8 + 2}{2}

\frac{x ^{2} + 5 x}{2} = 102

(x + 2)^{2} = 144

x^{2} + 8 x - 1

x^{2} + 8 x - 9

x, x^{2} + y^{2} - 6 x - 4 y - z + 5 = 0

What are the solutions to the equation -2x^2+16x-31=0 ?
The solutions to the equation -2x^2+16x-31=0 are x=(8-sqrt(2))/2 ,x=(8+sqrt(2))/2
Find the zeros of -2x^2+16x-31=0
The zeros of -2x^2+16x-31=0 are x=(8-sqrt(2))/2 ,x=(8+sqrt(2))/2