What are the solutions to the equation (x^2+5x)/2 =102 ?

The solutions to the equation (x^2+5x)/2 =102 are x=12,x=-17

Find the zeros of (x^2+5x)/2 =102

The zeros of (x^2+5x)/2 =102 are x=12,x=-17

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\frac{x ^{2} + 5 x}{2} = 102

x = 12, x = - 17

Solution steps

\frac{x ^{2} + 5 x}{2} = 102

Multiply both sides by

2

x^{2} + 5 x = 204

Move

204

to the left side

x^{2} + 5 x - 204 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 204 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 204) = 29

x_{1, 2} = \frac{- 5 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 29}{2 \cdot 1}, x_{2} = \frac{- 5 - 29}{2 \cdot 1}

x = \frac{- 5 + 29}{2 \cdot 1} : 12

x = \frac{- 5 - 29}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 12, x = - 17

(x + 2)^{2} = 144

x^{2} + 8 x - 1

x^{2} + 8 x - 9

x, x^{2} + y^{2} - 6 x - 4 y - z + 5 = 0

- z^{2} + 9 z - 20 = 0

What are the solutions to the equation (x^2+5x)/2 =102 ?
The solutions to the equation (x^2+5x)/2 =102 are x=12,x=-17
Find the zeros of (x^2+5x)/2 =102
The zeros of (x^2+5x)/2 =102 are x=12,x=-17