What are the solutions to the equation -z^2+9z-20=0 ?

The solutions to the equation -z^2+9z-20=0 are z=4,z=5

Find the zeros of -z^2+9z-20=0

The zeros of -z^2+9z-20=0 are z=4,z=5

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- z^{2} + 9 z - 20 = 0

z = 4, z = 5

Solution steps

- z^{2} + 9 z - 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 20) = 1

z_{1, 2} = \frac{- 9 \pm 1}{2 ( - 1 )}

Separate the solutions

z_{1} = \frac{- 9 + 1}{2 ( - 1 )}, z_{2} = \frac{- 9 - 1}{2 ( - 1 )}

z = \frac{- 9 + 1}{2 ( - 1 )} : 4

z = \frac{- 9 - 1}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

z = 4, z = 5

100 = - 16 t^{2} + 96 t

n^{2} + 20 n + 400 = 925

x^{2} = 1 7^{2} - 8^{2}

16 x^{2} + 56 x

2 x^{2} - 100 + 1200 = 0

What are the solutions to the equation -z^2+9z-20=0 ?
The solutions to the equation -z^2+9z-20=0 are z=4,z=5
Find the zeros of -z^2+9z-20=0
The zeros of -z^2+9z-20=0 are z=4,z=5