What are the solutions to the equation n^2+20n+400=925 ?

The solutions to the equation n^2+20n+400=925 are n=15,n=-35

Find the zeros of n^2+20n+400=925

The zeros of n^2+20n+400=925 are n=15,n=-35

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n^{2} + 20 n + 400 = 925

n = 15, n = - 35

Solution steps

n^{2} + 20 n + 400 = 925

Move

925

to the left side

n^{2} + 20 n - 525 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 525 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 525) = 50

n_{1, 2} = \frac{- 20 \pm 50}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 20 + 50}{2 \cdot 1}, n_{2} = \frac{- 20 - 50}{2 \cdot 1}

n = \frac{- 20 + 50}{2 \cdot 1} : 15

n = \frac{- 20 - 50}{2 \cdot 1} : - 35

The solutions to the quadratic equation are:

n = 15, n = - 35

x^{2} = 1 7^{2} - 8^{2}

16 x^{2} + 56 x

2 x^{2} - 100 + 1200 = 0

0 = 12 x^{2} - 12 x - 24

(2 x + 1)^{2} - (x - 3)^{2} = 0

What are the solutions to the equation n^2+20n+400=925 ?
The solutions to the equation n^2+20n+400=925 are n=15,n=-35
Find the zeros of n^2+20n+400=925
The zeros of n^2+20n+400=925 are n=15,n=-35