What are the solutions to the equation 3z^2+6z+3=0 ?

The solutions to the equation 3z^2+6z+3=0 are z=-1

Find the zeros of 3z^2+6z+3=0

The zeros of 3z^2+6z+3=0 are z=-1

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3 z^{2} + 6 z + 3 = 0

z = - 1

Solution steps

3 z^{2} + 6 z + 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

z_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

z = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

z = - 1

The solution to the quadratic equation is:

z = - 1

r, r^{2} - 2 r + 2 = 0

x = \frac{1}{2} (0.004) (5 - 5000 x - 0.3)^{2}

x, x^{2} y^{2} - 16 x y^{2} + 64 y^{2} = x^{2} + 2 x - 15

0 = 12 x^{2} - 84 x + 104

0 = 43 - 4 t - 5 t^{2}

What are the solutions to the equation 3z^2+6z+3=0 ?
The solutions to the equation 3z^2+6z+3=0 are z=-1
Find the zeros of 3z^2+6z+3=0
The zeros of 3z^2+6z+3=0 are z=-1