What are the solutions to the equation 0=x^2+8x+20 ?

The solutions to the equation 0=x^2+8x+20 are x=-4+2i,x=-4-2i

Find the zeros of 0=x^2+8x+20

The zeros of 0=x^2+8x+20 are x=-4+2i,x=-4-2i

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0 = x^{2} + 8 x + 20

x = - 4 + 2 i, x = - 4 - 2 i

Solution steps

0 = x^{2} + 8 x + 20

Switch sides

x^{2} + 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 20 : 4 i

x_{1, 2} = \frac{- 8 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 4 i}{2 \cdot 1}

x = \frac{- 8 + 4 i}{2 \cdot 1} : - 4 + 2 i

x = \frac{- 8 - 4 i}{2 \cdot 1} : - 4 - 2 i

The solutions to the quadratic equation are:

x = - 4 + 2 i, x = - 4 - 2 i

(2 y + 3) (y - 9) = 0

y, (1 + \frac{x}{2})^{2} + 3^{2} = y^{2}

- 4.9 x^{2} + 30 x + 200 = 0

(x^{2} - 2 x - 2) = 0

x^{2} - 3 x = x - 1

What are the solutions to the equation 0=x^2+8x+20 ?
The solutions to the equation 0=x^2+8x+20 are x=-4+2i,x=-4-2i
Find the zeros of 0=x^2+8x+20
The zeros of 0=x^2+8x+20 are x=-4+2i,x=-4-2i